X^2+(x+1)=(x+2)

Solution for X^2+(x+1)=(x+2) equation:

Simplifying
X2 + (x + 1) = (x + 2)

Reorder the terms:
X2 + (1 + x) = (x + 2)

Remove parenthesis around (1 + x)
X2 + 1 + x = (x + 2)

Reorder the terms:
1 + X2 + x = (x + 2)

Reorder the terms:
1 + X2 + x = (2 + x)

Remove parenthesis around (2 + x)
1 + X2 + x = 2 + x

Add '-1x' to each side of the equation.
1 + X2 + x + -1x = 2 + x + -1x

Combine like terms: x + -1x = 0
1 + X2 + 0 = 2 + x + -1x
1 + X2 = 2 + x + -1x

Combine like terms: x + -1x = 0
1 + X2 = 2 + 0
1 + X2 = 2

Solving
1 + X2 = 2

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + X2 = 2 + -1

Combine like terms: 1 + -1 = 0
0 + X2 = 2 + -1
X2 = 2 + -1

Combine like terms: 2 + -1 = 1
X2 = 1

Simplifying
X2 = 1

Take the square root of each side:
X = {-1, 1}